From: Brendan Jurd Date: Mon, 1 Oct 2018 06:52:10 +0000 (+1000) Subject: Fix name of argument in docs for functools.reduce(). (#9634) X-Git-Tag: v3.8.0a1~854 X-Git-Url: https://granicus.if.org/sourcecode?a=commitdiff_plain;h=9df100286b35f1f9fa85976d573981f558805b3f;p=python Fix name of argument in docs for functools.reduce(). (#9634) --- diff --git a/Doc/library/functools.rst b/Doc/library/functools.rst index 214d57334c..7d59ec9187 100644 --- a/Doc/library/functools.rst +++ b/Doc/library/functools.rst @@ -280,14 +280,14 @@ The :mod:`functools` module defines the following functions: .. function:: reduce(function, iterable[, initializer]) - Apply *function* of two arguments cumulatively to the items of *sequence*, from - left to right, so as to reduce the sequence to a single value. For example, + Apply *function* of two arguments cumulatively to the items of *iterable*, from + left to right, so as to reduce the iterable to a single value. For example, ``reduce(lambda x, y: x+y, [1, 2, 3, 4, 5])`` calculates ``((((1+2)+3)+4)+5)``. The left argument, *x*, is the accumulated value and the right argument, *y*, is - the update value from the *sequence*. If the optional *initializer* is present, - it is placed before the items of the sequence in the calculation, and serves as - a default when the sequence is empty. If *initializer* is not given and - *sequence* contains only one item, the first item is returned. + the update value from the *iterable*. If the optional *initializer* is present, + it is placed before the items of the iterable in the calculation, and serves as + a default when the iterable is empty. If *initializer* is not given and + *iterable* contains only one item, the first item is returned. Roughly equivalent to::