From: Andrew M. Kuchling <amk@amk.ca>
Date: Wed, 20 Dec 2006 19:57:10 +0000 (+0000)
Subject: [Bug #1619674] Make sum() use the term iterable, not sequence
X-Git-Tag: v2.6a1~2349
X-Git-Url: https://granicus.if.org/sourcecode?a=commitdiff_plain;h=1be2ac9cd6e72dd5116a24d173b66f9ae4ec51f0;p=python

[Bug #1619674] Make sum() use the term iterable, not sequence
---

diff --git a/Doc/lib/libfuncs.tex b/Doc/lib/libfuncs.tex
index dc52915c92..4f41002508 100644
--- a/Doc/lib/libfuncs.tex
+++ b/Doc/lib/libfuncs.tex
@@ -1087,11 +1087,11 @@ class C:
   string, \code{''}.
 \end{funcdesc}
 
-\begin{funcdesc}{sum}{sequence\optional{, start}}
-  Sums \var{start} and the items of a \var{sequence}, from left to
-  right, and returns the total.  \var{start} defaults to \code{0}.
-  The \var{sequence}'s items are normally numbers, and are not allowed
-  to be strings.  The fast, correct way to concatenate sequence of
+\begin{funcdesc}{sum}{iterable\optional{, start}}
+  Sums \var{start} and the items of an \var{iterable} from left to
+  right and returns the total.  \var{start} defaults to \code{0}.
+  The \var{iterable}'s items are normally numbers, and are not allowed
+  to be strings.  The fast, correct way to concatenate a sequence of
   strings is by calling \code{''.join(\var{sequence})}.
   Note that \code{sum(range(\var{n}), \var{m})} is equivalent to
   \code{reduce(operator.add, range(\var{n}), \var{m})}