pid = strtol(argv[argc],&endp,10);
if(!*endp){
if(!kill((pid_t)pid,signo)) continue;
+ // The UNIX standard contradicts itself. If at least one process
+ // is matched for each PID (as if processes could share PID!) and
+ // "the specified signal was successfully processed" (the systcall
+ // returned zero?) for at least one of those processes, then we must
+ // exit with zero. Note that an error might have also occured.
+ // The standard says we return non-zero if an error occurs. Thus if
+ // killing two processes gives 0 for one and EPERM for the other,
+ // we are required to return both zero and non-zero. Quantum kill???
exitvalue = 1;
continue;
}