Fix text about int() with octal numbers. Closes #21212.

diff --git a/Doc/faq/programming.rst b/Doc/faq/programming.rst
index d514a80e4aafafb8069abf32d95ae19c91ae72ae..9f49ba8851abb5305f20e7e6de301ea6a241aec9 100644 (file)
--- a/Doc/faq/programming.rst
+++ b/Doc/faq/programming.rst
@@ -711,7 +711,7 @@ By default, these interpret the number as decimal, so that ``int('0144') ==
 144`` and ``int('0x144')`` raises :exc:`ValueError`. ``int(string, base)`` takes
 the base to convert from as a second optional argument, so ``int('0x144', 16) ==
 324``.  If the base is specified as 0, the number is interpreted using Python's
-rules: a leading '0' indicates octal, and '0x' indicates a hex number.
+rules: a leading '0o' indicates octal, and '0x' indicates a hex number.
 
 Do not use the built-in function :func:`eval` if all you need is to convert
 strings to numbers.  :func:`eval` will be significantly slower and it presents a