If a unsigned with all 4 bytes non-0 was passed to outputHex(), there
were two off-by-ones in it:
- Both MaxPos and Pos left space for the final \0, which left the buffer
one byte to small. Set MaxPos to 16 instead of 15 to fix.
- The `assert(Pos >= 0);` was after a `Pos--`, move it up one line.
Since valid Unicode codepoints are <= 0x10ffff, this could never really
happen in practice.
Found by oss-fuzz.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@358856
91177308-0d34-0410-b5e6-
96231b3b80d8
char TempBuffer[17];
::memset(TempBuffer, 0, sizeof(TempBuffer));
- constexpr int MaxPos = 15;
+ constexpr int MaxPos = sizeof(TempBuffer) - 1;
- int Pos = MaxPos - 1;
+ int Pos = MaxPos - 1; // TempBuffer[MaxPos] is the terminating \0.
while (C != 0) {
for (int I = 0; I < 2; ++I) {
writeHexDigit(&TempBuffer[Pos--], C % 16);
C /= 16;
}
TempBuffer[Pos--] = 'x';
- TempBuffer[Pos--] = '\\';
assert(Pos >= 0);
+ TempBuffer[Pos--] = '\\';
}
OS << StringView(&TempBuffer[Pos + 1]);
}
??_C@_0CC@MBPKDIAM@a?$AA?$AA?$AAb?$AA?$AA?$AAc?$AA?$AA?$AAd?$AA?$AA?$AAe?$AA?$AA?$AAf?$AA?$AA?$AAg?$AA?$AA?$AAh?$AA?$AA?$AA@
; CHECK: u"a\0b\0c\0d\0e\0f\0g\0h\0"...
+
+; This is technically not a valid u32 string since the character in it is not
+; <= 0x10FFFF like unicode demands. (Also, the crc doesn't match the contents.)
+; It's here because this input used to cause a stack overflow in outputHex().
+
+; FIXME: The demangler currently writes for \x codes for a single U string
+; character. That's incorrect since that would mangle two four characters.
+
+??_C@_07LJGFEJEB@D3?$CC?$BB?$AA?$AA?$AA?$AA@)
+; CHECK: U"\x11\x22\x33\x44"