Make an iterator that drops elements from the iterable as long as
the predicate is true; afterwards, returns every element. Note,
the iterator does not produce \emph{any} output until the predicate
- is true, so it may have a lengthy start-up time. Equivalent to:
+ first becomes false, so it may have a lengthy start-up time. Equivalent to:
\begin{verbatim}
def dropwhile(predicate, iterable):
return izip(mapping.iterkeys(), mapping.itervalues())
def nth(iterable, n):
- "Returns the nth item or raise IndexError"
- return list(islice(iterable, n, n+1))[0]
+ "Returns the nth item or raise StopIteration"
+ return islice(iterable, n, None).next()
def all(seq, pred=None):
"Returns True if pred(x) is true for every element in the iterable"