Don't insist that float('1'*10000) raises an exception.
if have_unicode:
self.assertEqual(float(str(" 3.14 ")), 3.14)
self.assertEqual(float(str(b" \u0663.\u0661\u0664 ",'raw-unicode-escape')), 3.14)
- # Implementation limitation in PyFloat_FromString()
- self.assertRaises(ValueError, float, str("1"*10000))
+ self.assertEqual(float("1"*10000), 1e10000) # Inf on both sides
@run_with_locale('LC_NUMERIC', 'fr_FR', 'de_DE')
def test_float_with_comma(self):
return NULL;
}
res = (*nb->nb_hex)(v);
- if (res && !PyString_Check(res)) {
+ if (res && !PyString_Check(res) && !PyUnicode_Check(res)) {
PyErr_Format(PyExc_TypeError,
"__hex__ returned non-string (type %.200s)",
res->ob_type->tp_name);
return NULL;
}
res = (*nb->nb_oct)(v);
- if (res && !PyString_Check(res)) {
+ if (res && !PyString_Check(res) && !PyUnicode_Check(res)) {
PyErr_Format(PyExc_TypeError,
"__oct__ returned non-string (type %.200s)",
res->ob_type->tp_name);