There is no reason to allow %00 to terminate a string, so do not allow it.
Otherwise, we end up returning arbitrary content in the string (that which is
after the %00) which is effectively hidden from callers and can escape sanity
checks and validation, and possible be used in tandem with a security
vulnerability to introduce a payload.
Helped-by: brian m. carlson <sandals@crustytoothpaste.net>
Signed-off-by: Matthew DeVore <matvore@google.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
if (c == '%' && (len < 0 || len >= 3)) {
int val = hex2chr(q + 1);
- if (0 <= val) {
+ if (0 < val) {
strbuf_addch(out, val);
q += 3;
len -= 3;