>>> _binary_float_to_ratio(-.25)
(-1, 4)
"""
+ # XXX Consider moving this to to floatobject.c
+ # with a name like float.as_intger_ratio()
if x == 0:
return 0, 1
else:
return '%s/%s' % (self.numerator, self.denominator)
+ """ XXX This section needs a lot more commentary
+
+ * Explain the typical sequence of checks, calls, and fallbacks.
+ * Explain the subtle reasons why this logic was needed.
+ * It is not clear how common cases are handled (for example, how
+ does the ratio of two huge integers get converted to a float
+ without overflowing the long-->float conversion.
+
+ """
+
def _operator_fallbacks(monomorphic_operator, fallback_operator):
"""Generates forward and reverse operators given a purely-rational
operator and a function from the operator module.
float must have the same hash as that float.
"""
+ # XXX since this method is expensive, consider caching the result
if self.denominator == 1:
# Get integers right.
return hash(self.numerator)