const CXXMethodDecl* Method = cast<CXXMethodDecl>(*Op);
if (Method->isStatic())
continue;
- // TODO: Skip templates? Or is this implicitly done due to parameter types?
+ if (Method->getPrimaryTemplate())
+ continue;
const FunctionProtoType *FnType =
Method->getType()->getAs<FunctionProtoType>();
assert(FnType && "Overloaded operator has no prototype.");
const FunctionProtoType *FnType = OpDecl->getType()->getAs<FunctionProtoType>();
assert(FnType && "Overloaded operator has no proto function type.");
assert(FnType->getNumArgs() == 1 && !FnType->isVariadic());
+
+ // Copy assignment operators must be non-templates.
+ if (OpDecl->getPrimaryTemplate() || OpDecl->getDescribedFunctionTemplate())
+ return;
+
QualType ArgType = FnType->getArgType(0);
if (const LValueReferenceType *Ref = ArgType->getAs<LValueReferenceType>())
ArgType = Ref->getPointeeType();
// const volatile X&, and either there are no other parameters
// or else all other parameters have default arguments (8.3.6).
if ((getNumParams() < 1) ||
- (getNumParams() > 1 && !getParamDecl(1)->hasDefaultArg()))
+ (getNumParams() > 1 && !getParamDecl(1)->hasDefaultArg()) ||
+ (getPrimaryTemplate() != 0) ||
+ (getDescribedFunctionTemplate() != 0))
return false;
const ParmVarDecl *Param = getParamDecl(0);