if (rcanon->getTypeClass() == Type::Reference)
rcanon = cast<ReferenceType>(rcanon)->getReferenceeType();
- // If the canonical type classes don't match, they can't be compatible
+ // If the canonical type classes don't match...
if (lcanon->getTypeClass() != rcanon->getTypeClass()) {
// For Objective-C, it is possible for two types to be compatible
// when their classes don't match (when dealing with "id"). If either type
// is an interface, we defer to objcTypesAreCompatible().
if (lcanon->isObjCInterfaceType() || rcanon->isObjCInterfaceType())
return objcTypesAreCompatible(lcanon, rcanon);
+
+ // C99 6.7.2.2p4: Each enumerated type shall be compatible with char,
+ // a signed integer type, or an unsigned integer type.
+ if ((lcanon->isEnumeralType() && rcanon->isIntegralType()) ||
+ (rcanon->isEnumeralType() && lcanon->isIntegralType()))
+ return true;
+
return false;
}
+ // The canonical type classes match.
switch (lcanon->getTypeClass()) {
case Type::Pointer:
return pointerTypesAreCompatible(lcanon, rcanon);
if (OldQType.getTypePtr()->getTypeClass() == Type::FunctionNoProto &&
Old->getResultType() == New->getResultType())
return New;
- if (OldQType == NewQType)
+ // Function types need to be compatible, not identical. This handles
+ // duplicate function decls like "void f(int); void f(enum X);" properly.
+ if (Context.functionTypesAreCompatible(OldQType, NewQType))
return New;
}