\lineiii{\var{a}.items()}
{a copy of \var{a}'s list of (\var{key}, \var{value}) pairs}
{(3)}
- \lineiii{\var{a}.keys()}{a copy of \var{a}'s list of keys}{(2)}
+ \lineiii{\var{a}.keys()}{a copy of \var{a}'s list of keys}{(3)}
\lineiii{\var{a}.update(\var{b})}
{\code{for k in \var{b}.keys(): \var{a}[k] = \var{b}[k]}}
{(4)}
- \lineiii{\var{a}.values()}{a copy of \var{a}'s list of values}{(2)}
+ \lineiii{\var{a}.values()}{a copy of \var{a}'s list of values}{(3)}
\lineiii{\var{a}.get(\var{k}\optional{, \var{x}})}
{\code{\var{a}[\var{k}]} if \code{\var{k} in \var{a}},
else \var{x}}
\method{keys()} and \method{values()} are called with no intervening
modifications to the dictionary, the two lists will directly
correspond. This allows the creation of \code{(\var{value},
-\var{key})} pairs using \function{map()}: \samp{pairs = map(None,
-\var{a}.values(), \var{a}.keys())}.
+\var{key})} pairs using \function{zip()}: \samp{pairs =
+zip(\var{a}.values(), \var{a}.keys())}.
\item[(4)] \var{b} must be of the same type as \var{a}.