{test whether every element in \var{t} is in \var{s}}
\hline
- \lineiii{\var{s}.union(\var{t})}{\var{s} | \var{t}}
+ \lineiii{\var{s}.union(\var{t})}{\var{s} \textbar{} \var{t}}
{new set with elements from both \var{s} and \var{t}}
\lineiii{\var{s}.intersection(\var{t})}{\var{s} \&\ \var{t}}
{new set with elements common to \var{s} and \var{t}}
\begin{tableiii}{c|c|l}{code}{Operation}{Equivalent}{Result}
\lineiii{\var{s}.union_update(\var{t})}
- {\var{s} |= \var{t}}
+ {\var{s} \textbar= \var{t}}
{return set \var{s} with elements added from \var{t}}
\lineiii{\var{s}.intersection_update(\var{t})}
{\var{s} \&= \var{t}}