on Invalid url check statement and versionchanged string in docs.
.. versionchanged:: 2.5
Added attributes to return value.
+ .. versionchanged:: 2.7
+ Added IPv6 URL parsing capabilities.
+
+
.. function:: parse_qs(qs[, keep_blank_values[, strict_parsing]])
Parse a query string given as a string argument (data of type
:rfc:`3986` - Uniform Resource Identifiers
This is the current standard (STD66). Any changes to urlparse module
should conform to this. Certain deviations could be observed, which are
- mostly due backward compatiblity purposes and for certain to de-facto
+ mostly due backward compatiblity purposes and for certain de-facto
parsing requirements as commonly observed in major browsers.
:rfc:`2732` - Format for Literal IPv6 Addresses in URL's.
for invalid_url in [
'http://::12.34.56.78]/',
'http://[::1/foo/',
+ 'ftp://[::1/foo/bad]/bad',
'http://[::1/foo/bad]/bad',
'http://[::ffff:12.34.56.78']:
- self.assertRaises(ValueError, lambda : urlparse.urlparse(invalid_url).hostname)
- self.assertRaises(ValueError, lambda : urlparse.urlparse(invalid_url))
+ self.assertRaises(ValueError, urlparse.urlparse, invalid_url)
def test_urldefrag(self):
for url, defrag, frag in [
url = url[i+1:]
if url[:2] == '//':
netloc, url = _splitnetloc(url, 2)
- if '[' in netloc :
- if not ']' in netloc: raise ValueError("Invalid IPv6 URL")
- if ']' in netloc:
- if not '[' in netloc: raise ValueError("Invalid IPv6 URL")
+ if (('[' in netloc and ']' not in netloc) or
+ (']' in netloc and '[' not in netloc)):
+ raise ValueError("Invalid IPv6 URL")
if allow_fragments and '#' in url:
url, fragment = url.split('#', 1)
if '?' in url:
if url[:2] == '//':
netloc, url = _splitnetloc(url, 2)
- if '[' in netloc:
- if not ']' in netloc: raise ValueError("Invalid IPv6 URL")
- if ']' in netloc:
- if not '[' in netloc: raise ValueError("Invalid IPv6 URL")
+ if (('[' in netloc and ']' not in netloc) or
+ (']' in netloc and '[' not in netloc)):
+ raise ValueError("Invalid IPv6 URL")
if allow_fragments and scheme in uses_fragment and '#' in url:
url, fragment = url.split('#', 1)
if scheme in uses_query and '?' in url: