httpd.serve_forever()
-Example of a small wsgiref-based web server::
-
- # Takes a path to serve from and an optional port number (defaults to 8000),
- # then tries to serve files. Mime types are guessed from the file names, 404
- # errors are raised if the file is not found.
- import sys
- import os
- import mimetypes
- from wsgiref import simple_server, util
-
- def app(environ, respond):
- fn = os.path.join(path, environ['PATH_INFO'][1:])
- if '.' not in fn.split(os.path.sep)[-1]:
- fn = os.path.join(fn, 'index.html')
- type = mimetypes.guess_type(fn)[0]
-
- if os.path.exists(fn):
- respond('200 OK', [('Content-Type', type)])
- return util.FileWrapper(open(fn, "rb"))
- else:
- respond('404 Not Found', [('Content-Type', 'text/plain')])
- return [b'not found']
-
- path = sys.argv[1]
- port = int(sys.argv[2]) if len(sys.argv) > 2 else 8000
- with simple_server.make_server('', port, app) as httpd:
- print("Serving {} on port {}, control-C to stop".format(path, port))
-
- # Serve until process is killed
- httpd.serve_forever()
+Example of a WSGI application serving the current directory, accept optional
+directory and port number (default: 8000) on the command line:
+
+.. literalinclude:: ../../Tools/scripts/serve.py
return [b'not found']
if __name__ == '__main__':
- path = sys.argv[1]
+ path = sys.argv[1] if len(sys.argv) > 1 else os.getcwd()
port = int(sys.argv[2]) if len(sys.argv) > 2 else 8000
httpd = simple_server.make_server('', port, app)
print("Serving {} on port {}, control-C to stop".format(path, port))
try:
httpd.serve_forever()
except KeyboardInterrupt:
- print("\b\bShutting down.")
+ print("Shutting down.")
+ httpd.server_close()