members of dependent contexts.
This permits cases where the names before and after the '::' in a
dependent inherited constructor using-declaration do not match, but
where we can nonetheless tell when parsing the template that a
constructor is being named. Under (open) core language DR 2070, such
cases will probably be ill-formed, but r335182 does not quite give
that result and didn't intend to change this, so restore the old
behavior for now.
git-svn-id: https://llvm.org/svn/llvm-project/cfe/trunk@335381
91177308-0d34-0410-b5e6-
96231b3b80d8
IdentifierInfo &Name);
ParsedType getConstructorName(IdentifierInfo &II, SourceLocation NameLoc,
- Scope *S, CXXScopeSpec &SS);
+ Scope *S, CXXScopeSpec &SS,
+ bool EnteringContext);
ParsedType getDestructorName(SourceLocation TildeLoc,
IdentifierInfo &II, SourceLocation NameLoc,
Scope *S, CXXScopeSpec &SS,
if (AllowConstructorName &&
Actions.isCurrentClassName(*Id, getCurScope(), &SS)) {
// We have parsed a constructor name.
- ParsedType Ty = Actions.getConstructorName(*Id, IdLoc, getCurScope(), SS);
+ ParsedType Ty = Actions.getConstructorName(*Id, IdLoc, getCurScope(), SS,
+ EnteringContext);
if (!Ty)
return true;
Result.setConstructorName(Ty, IdLoc, IdLoc);
<< FixItHint::CreateRemoval(
SourceRange(TemplateId->LAngleLoc, TemplateId->RAngleLoc));
ParsedType Ty = Actions.getConstructorName(
- *TemplateId->Name, TemplateId->TemplateNameLoc, getCurScope(), SS);
+ *TemplateId->Name, TemplateId->TemplateNameLoc, getCurScope(), SS,
+ EnteringContext);
if (!Ty)
return true;
Result.setConstructorName(Ty, TemplateId->TemplateNameLoc,
ParsedType Sema::getConstructorName(IdentifierInfo &II,
SourceLocation NameLoc,
- Scope *S, CXXScopeSpec &SS) {
+ Scope *S, CXXScopeSpec &SS,
+ bool EnteringContext) {
CXXRecordDecl *CurClass = getCurrentClass(S, &SS);
assert(CurClass && &II == CurClass->getIdentifier() &&
"not a constructor name");
+ // When naming a constructor as a member of a dependent context (eg, in a
+ // friend declaration or an inherited constructor declaration), form an
+ // unresolved "typename" type.
+ if (CurClass->isDependentContext() && !EnteringContext) {
+ QualType T = Context.getDependentNameType(ETK_None, SS.getScopeRep(), &II);
+ return ParsedType::make(T);
+ }
+
if (SS.isNotEmpty() && RequireCompleteDeclContext(SS, CurClass))
return ParsedType();
using T::T; // expected-error {{type 'int' cannot be used prior to '::' because it has no members}}
};
UsingIntTemplate<int> uit; // expected-note {{here}}
+
+ // This case is odd: we don't name the constructor of a dependent base as
+ // Base::Base, but we still happen to have enough information to identify
+ // when parsing the template that we're inheriting constructors.
+ //
+ // FIXME: Once CWG 2070 is resolved, check whether this case should be
+ // accepted or not.
+ namespace DependentCtorName {
+ template <typename T> struct B { B(int); };
+ template <typename T> struct A : B<T> {
+ using X = B<T>;
+ using X::B;
+ };
+ A<int> ab = 0;
+ }
#endif
}