if n > 16384:
# The payload is large so Nagle's algorithm won't be triggered
# and we'd better avoid the cost of concatenation.
- chunks = [header, buf]
- elif n > 0:
+ self._send(header)
+ self._send(buf)
+ else:
# Issue # 20540: concatenate before sending, to avoid delays due
# to Nagle's algorithm on a TCP socket.
- chunks = [header + buf]
- else:
- # This code path is necessary to avoid "broken pipe" errors
- # when sending a 0-length buffer if the other end closed the pipe.
- chunks = [header]
- for chunk in chunks:
- self._send(chunk)
+ # Also note we want to avoid sending a 0-length buffer separately,
+ # to avoid "broken pipe" errors if the other end closed the pipe.
+ self._send(header + buf)
def _recv_bytes(self, maxsize=None):
buf = self._recv(4)